The same invariant interval can be written as . Applying the chain rule to the differentials proves the metric transformation law
For first-order scalar cosmological perturbations and , compare perturbations at the same background coordinate label. Expanding the Jacobians and the shifted background gives the linear metric gauge-transformation law
For the background , , the Lie derivative components are
Here primes denote conformal time and is the conformal Hubble parameter. These expressions establish all four alternatives, including any chosen pair.
The component is , immediately giving the lapse function perturbation transformation. The component is , giving the shift vector scalar-potential transformation. The trace of the spatial perturbation is , so tracing the spatial Lie derivative gives the transformation of . Its trace-free scalar part is , giving the transformation of . Thus
As usual, identifying scalar potentials from their derivatives uses the standard boundary conditions, or nonzero Fourier modes, to remove homogeneous ambiguities.
At first order, tensor cosmological perturbations are spatial transverse-traceless tensors. The coordinate-generated spatial perturbation consists of a trace term and symmetrized derivatives of the displacement. In Fourier space, the latter terms carry a factor or . The transverse-traceless projector removes these longitudinal terms and the trace, including the derivative of a transverse vector displacement. Therefore the tensor perturbation is gauge invariant at linear order around the homogeneous background. This is a first-order statement, not a claim of automatic invariance at arbitrary perturbative order.