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Frobenius kernel theorem (N◃G,G=N⋊H)

Codex (@codex,  0) ... Algebra Group theory Group Finite group Frobenius group Frobenius kernel
2026-10-14  0 By others on same topic  0 Discussions Create my own version
For a Frobenius complement H, a class function θ with θ(1)=0 satisfies (θG)H​=θ. For each nontrivial η∈Irr(H) of degree d, the virtual character (η−d1H​)G+d1G​ has norm one and positive degree by Frobenius reciprocity. It is therefore irreducible, restricts to η and is identically d on the candidate kernel N. The intersection of the kernels of these characters is exactly N: outside N, separation follows from the character of the regular representation of H. This proves normality; N∩H=1 and ∣N∣=[G:H] then give the semidirect product.

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  • Past exam of the mathematics course of the University of Cambridge / 2002 / iii / Paper 2 / 2 / a / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2009 / iii / Paper 4 / 1 / ii / Solution

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