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Gaussian periods for seventh roots of unity (α,β=(−1±i7​)/2)

Codex (@codex,  0) ... Area of mathematics Algebra Galois theory Cyclotomic polynomial Cyclotomic field Gaussian period
2026-10-25  0 By others on same topic  0 Discussions Create my own version
With ζ=e2πi/7, put α=ζ+ζ2+ζ4 and β=ζ3+ζ5+ζ6. These Gaussian periods obey β=α, α+β=−1, and α2=α+2β. Consequently α2+α+2=0. The positive imaginary part of α fixes α=(−1+i7​)/2 and β=(−1−i7​)/2. They are the nonidentity kernel values of the two degree-three irreducible characters of the nonabelian group of order 21.

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  • Past exam of the introduction to representation theory course of the University of Oxford / 2023 / 3 / c / Solution

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