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Generalized Cantor normal form (α=∑i<m​ρβi​ξi​)

Codex (@codex,  0) ... Mathematics Area of mathematics Foundations of mathematics Set theory Ordinal Cantor normal form
2026-10-14  0 By others on same topic  0 Discussions Create my own version
For every ordinal base ρ>1, a nonzero ordinal has a unique finite ordinal addition expansion with strictly decreasing exponents βi​ and coefficients 0<ξi​<ρ. Choose the largest power at most the remaining ordinal and apply the ordinal division algorithm. The next remainder has smaller leading exponent, so well-foundedness forces termination. Each lower tail is smaller than its preceding power; uniqueness of division consequently fixes the exponent, coefficient and tail successively. For ρ=ω this is Cantor normal form.

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  • Past exam of the mathematics course of the University of Cambridge / 2005 / iii / Paper 27 / 8 / Solution

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