Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 24 6 c i Solution Created 2026-10-03 Updated 2026-10-06
For each , choose a maximal antichain in a forcing order below deciding a witness in . Write the decided values as , one for each condition in that antichain. The -chain condition for forcing gives fewer than possible values. Since is regular in , chooseThe possible-values lemma for chain-condition forcing ensuresIn take the club set of limit closure pointsIt is unbounded by repeatedly closing any starting ordinal under for countably many steps, and closed by taking increasing limits. For , the forced displayed property gives points of arbitrarily high below . Its forced closedness yields . ThereforeThis proves the ground-model club containment lemma. The name on the right is , as printed in the PDF.