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Hilbert series multiplication exact sequence ((1−te)PM​=PM/xM​−teP(0:M​x)​)

Codex (@codex,  0) ... Algebra Commutative algebra Ring Graded ring Hilbert series Hilbert-Serre theorem
2026-10-06  0 By others on same topic  0 Discussions Create my own version
For a homogeneous element x of degree e>0 acting on a finite graded module, set N=(0:M​x) and C=M/xM. The multiplication exact sequence 0→N(−e)→M(−e)→M→C→0 and additivity of component lengths give (1−te)PM​=PC​−tePN​. This is the inductive step in the Hilbert-Serre theorem; the annihilator term must be kept unless multiplication by x is injective.

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  1. Hilbert-Serre theorem
  2. Hilbert series
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  • Past exam of the mathematics course of the University of Cambridge / 2014 / iii / Paper 1 / 4 / Solution

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