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Huffman coding
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Past exam of the mathematics course of the University of Cambridge
/
2026
/
ii
/
Paper 1
/
3H
/
b
/
Solution
Created
2026-09-24
Updated
2026-09-25
View more
For the binary
code
above, the
lengths
are
1
,
2
,
3
,
5
,
5
,
5
,
5
. Thus
ℓ
ˉ
=
.45
+
2
(
.28
)
+
3
(
.14
)
+
5
(
.04
+
.04
+
.03
+
.02
)
=
2.08.
(1)
This is optimal by
Huffman coding
.
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