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 Incoming links: Identity monad

The identity monad embeds a value unchanged and sequences by ordinary application:

type IdM a = a
result :: a -> IdM a
result x = x
bind :: IdM a -> (a -> IdM b) -> IdM b
bind x f = f x

All three monad laws reduce to substitution in function application. There is no additional program state, failure alternative or continuation layer:

result (x) = x, x ▹ f = f (x) .

The equivalence holds for every lawful computational monad with the semantic equations above. In particular, effects in

e_{1}

are neither discarded nor evaluated twice. Fix an initial semantic environment

ρ

, and write

E = eval (e_{1}) ρ, ρ_{v} = extend (ρ, [(x, v)]), F (v) = eval (e_{2}) ρ_{v} .

Expanding Let and Val gives

eval (let val x = e_{1} in e_{2}) ρ = (E ▹ (λ v . result (ρ_{v}))) ▹ (λ ρ^{'} . eval (e_{2}) ρ^{'}) = E ▹ (λ v . result (ρ_{v}) ▹ (λ ρ^{'} . eval (e_{2}) ρ^{'})) = E ▹ F .

The two steps use associativity and left identity from the monad laws.

For the application, evaluating the lambda abstraction yields result c, where the programming closure

c

satisfies

apply (c, [v]) = F (v)

. The singleton argument evaluator reduces to

evalArgs ([e_{1}]) ρ = E ▹ (λ v . result ([]) ▹ (λ v s . result (v : v s))) = E ▹ (λ v . result ([v])) .

Use left identity to remove the initial result c, then associativity and left identity again:

eval ((lambda (x) e_{2}) e_{1}) ρ = (E ▹ (λ v . result ([v]))) ▹ (λ v s . apply (c, v s)) = E ▹ (λ v . result ([v]) ▹ (λ v s . apply (c, v s))) = E ▹ F .

Consequently,

eval (let val x = e_{1} in e_{2}) ρ = eval ((lambda (x) e_{2}) e_{1}) ρ for every lawful M .

The argument relies on the lambda abstraction itself being effect-free, as specified in part (a), and on using the same semantic environment for

e_{1}

on each side. No commutativity of effects is assumed. In particular, the proof applies to state monads, exceptions and continuation monads, not merely to the identity monad.