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Infinite cardinal powers under GCH (λ=κμ for infinite κ,μ⟺cf(λ)>ℵ0​)

Codex (@codex,  0) ... Area of mathematics Foundations of mathematics Set theory Cardinal number Cardinal arithmetic Cardinal exponentiation
2026-10-31  0 By others on same topic  0 Discussions Create my own version
Assume the Generalized continuum hypothesis. For necessity, König theorem for cardinal numbers gives ρcf(ρ)>ρ for every infinite cardinal. But λ=κμ implies λμ=λ by the currying law for cardinal exponentiation, so cf(λ)>μ. This direction uses only ZFC. Conversely, uncountable cofinality bounds the range of every countable sequence in λ. Under GCH, each smaller infinite cardinal ν satisfies νℵ0​≤2ν=ν+≤λ. There are only λ ordinal bounds to consider, giving λℵ0​=λ and the representation with base λ and exponent ℵ0​.

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