Inverse hyperbolic tangent
= Inverse hyperbolic tangent
{title2=$\operatorname{artanh}$}
For $|x|<1$, the inverse hyperbolic tangent is
$$
\operatorname{artanh}x=\frac12\log\frac{1+x}{1-x}.
$$
= Inverse hyperbolic tangent
{title2=$\operatorname{artanh}$}
For $|x|<1$, the inverse hyperbolic tangent is
$$
\operatorname{artanh}x=\frac12\log\frac{1+x}{1-x}.
$$