Inverse hyperbolic tangent ( $artanh$ )

For

∣ x ∣ < 1

, the inverse hyperbolic tangent is

artanh x = \frac{1}{2} lo g \frac{1 + x}{1 - x} .

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Past exam of the mathematics course of the University of Cambridge / 2004 / iii / Paper 74 / 2 / Solution
Past exam of the mathematics course of the University of Cambridge / 2019 / ia / Paper 2 / 8C / c / Solution

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