Laplace asymptotic for the derivative of the Gamma function
= Laplace asymptotic for the derivative of the Gamma function
After $t=zs$, the phase in the integral for $\Gamma'(z)$ becomes $\log s-s$, with maximum $-1$ and second derivative $-1$ at $s=1$. Hence
$$
\Gamma'(z)\sim\sqrt{\frac{2\pi}{z}}e^{z\log z-z}\log z.
$$