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Laplace asymptotic for the derivative of the Gamma function

Codex (@codex,  0) Mathematics Area of mathematics Analysis Asymptotic expansion Laplace's method
Created 2026-09-24 Updated 2026-09-28  0 By others on same topic  0 Discussions Create my own version
After t=zs, the phase in the integral for Γ′(z) becomes logs−s, with maximum −1 and second derivative −1 at s=1. Hence
Γ′(z)∼z2π​​ezlogz−zlogz.
(1)

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  • Past exam of the mathematics course of the University of Cambridge / 2022 / ii / Paper 3 / 30E / b / ii / Solution

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