Past exam of the mathematics course of the University of Cambridge 2004 iii Paper 15 1 Solution Created 2026-10-03 Updated 2026-10-14
Choose an oriented basis of the period lattice, so . The Weierstrass elliptic function is constructed by the normally convergent seriesOn compact sets away from the lattice the summands are , which is summable over a plane lattice. It is even, has double poles at the lattice with zero residues, and is periodic. To check periodicity without splitting divergent series, differentiate termwise: is invariant under lattice shifts. Hence is constant; evenness evaluated at makes this constant zero.
The Weierstrass sigma function is the canonical productIts logarithmic tails are likewise , so it defines an entire function with simple zeros exactly at the lattice and . Pairing opposite lattice factors makes it odd. Its logarithmic derivative is the Weierstrass zeta functionThus is constant. Integrating this identity and evaluating the sigma ratio at givesIntegration of zeta around a fundamental cell, containing one pole of residue one, gives the Legendre relation for Weierstrass quasi-periods . These formulas explain why sigma itself is not an elliptic function, but balanced products of translates can be.
For completeness, the basic algebraic property of wp is , where and . The identity follows by canceling the principal parts using the Laurent expansion: the difference is an entire elliptic function, hence constant, and its constant term is zero. The discriminant is nonzero; equivalently the three half-period values are distinct. These properties lead to the cubic embedding in 2(ii).
Now let be a nonzero meromorphic function on the torus and lift it to a periodic meromorphic function on the plane. Its logarithmic derivative is periodic. Choose a fundamental parallelogram with no zero or pole on its boundary. The residue theorem applied to gives equality of the total zero and pole multiplicities. Applied to , it gives the difference of the sums of the zero and pole lifts. Pairing opposite edges explicitly yieldsEach integral of on the right is times an integer, since its endpoint values of coincide and the image path avoids zero. Therefore the zero sum and pole sum agree in .
Conversely, suppose the point sums agree modulo the lattice. Change one chosen lift of a point by a lattice element so the two sums agree exactly in ; this changes no point of the torus. Thenhas the prescribed divisor. Its multiplier under either basis period is , so it descends to the torus. Repetitions contribute their appropriate multiplicities. This proves the principality criterion on a complex elliptic curve:There is an implicit qualification in the wording about separate zero and pole divisors: their supports must be disjoint. If a point occurs on both lists, cancel common multiplicities first when prescribing the divisor difference. A function cannot simultaneously have a zero and a pole at the same point; for example identical one-point lists satisfy the sum condition but do not specify separate zero and pole divisors. For , any nonzero constant supplies the empty divisor.