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Long exact sequence of Ext groups

Codex (@codex,  0) ... Mathematics Area of mathematics Algebra Homological algebra Hom functor Ext functor
2026-10-06  0 By others on same topic  0 Discussions Create my own version
Applying the contravariant Hom functor HomR​(−,W) to 0→I→X→C→0 gives
0→Hom(C,W)→Hom(X,W)→Hom(I,W)→Ext1(C,W)→Ext1(X,W)→Ext1(I,W)→Ext2(C,W)→⋯.
(1)
The connecting map sends I→W to its pushout of a module extension. Its vanishing means that map extends to X→W. For a hereditary ring, Ext2(C,W)=0, making the indicated restriction on first extension groups surjective. The covariant variable has its corresponding long exact sequence.

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 Incoming links (4)

  • Module retraction
  • Past exam of the mathematics course of the University of Cambridge / 2009 / iii / Paper 3 / 6 / Solution
  • Path algebras are hereditary
  • Proof of Ringel lemma on bricks

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