Past exam of the mathematics course of the University of Cambridge 2007 iii Paper 48 5 b iii Solution Created 2026-10-03 Updated 2026-10-14
The event (m=N) represents no change within the observed sequence: every observation belongs to the first-rate segment, and the second-rate segment is empty. It is not the event ; under continuous independent rate priors that exact equality has posterior probability zero. The endpoint is instead a distinct index value with positive prior mass.
For retained Markov chain Monte Carlo draws , the direct estimate isIts consistency follows from the ergodic theorem for a positive Harris recurrent Markov chain. The draws are correlated, so an independent-binomial standard error would generally be incorrect; uncertainty should account for the Markov chain Monte Carlo asymptotic variance.
A conditional Monte Carlo alternative averages the conditional probability from the preceding solution:The tower property of conditional expectation shows that its posterior expectation is the same target. This replaces an indicator by its conditional expectation; for correlated chains one should assess efficiency rather than automatically assume its entire asymptotic variance is smaller.
An exact finite-sum check is available by integrating out both rates. The marginal posterior weights of a Poisson count change point areThese follow from the Gamma function integral . All omitted prior-normalization and factorial factors are independent of , so they cancel from this ratio. This exact calculation provides a useful independent check on either simulation estimate.