Maxwell speed distribution
= Maxwell speed distribution
{c}
{title2=$g(v)$}
Integrating the <Maxwell-Boltzmann velocity distribution> over directions gives
$$
g(v)=4\pi v^2
\left(\frac{m}{2\pi k_BT}\right)^{3/2}
e^{-mv^2/(2k_BT)},
\qquad v\geq0.
$$