Maxwell speed distribution ( $g (v)$ )

g (v) = 4 π v^{2} (\frac{m}{2 π k _{B} T})^{3/2} e^{- m v^{2} / (2 k_{B} T)}, v \geq 0.

Most probable speed in the Maxwell distribution ( $v_{mp}$ )

The maximum of the Maxwell speed distribution occurs at

v_{mp} = \frac{2 k _{B} T}{m} .

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