Past exam of the mathematics course of the University of Cambridge 2010 iii Paper 6 3 Solution Created 2026-10-03 Updated 2026-10-14
We construct a normalized positive translation-invariant functional on and then represent it by a measure. The main step is a finite matching in a graph argument, for which we establish all the covering-net properties.
Let be an open neighbourhood of the identity in the compact topological group . The sets , , form an open cover. Compactness supplies a finite set with . Among all such finite sets choose one of smallest cardinality, denoted . This is a minimal left covering net of a compact group. If , then , and has the same cardinality. Hence is also minimal for the same .
Let be any two minimal left covering nets of a compact group for . They both have cardinality . Form a bipartite graph by joining to whenever . For a subset , let be its set of neighbours. Every point of lies in some with ; that is a neighbour of a member of . Thereforeand is still a left covering set. By minimality,Thus . Hall's marriage theorem gives a bijection with for every . If at an intersection point, thenThis proves the matching minimal covering nets of a compact group property, including the estimate needed below.
For a continuous complex-valued function on , defineContinuity and compactness imply as identity neighbourhoods shrink. Here is the uniformity argument: continuity of at each gives a product neighbourhood where its absolute value is small; finitely many of the first-coordinate neighbourhoods cover , and intersecting the corresponding second-coordinate neighbourhoods gives one that works for every .
Matched pairs therefore giveIn particular, with ,The estimate holds for every ; no commutativity of is being assumed.
Direct the open identity neighbourhoods by reverse inclusion and choose a minimal left covering net of a compact group for each. The values lie in the closed complex disk of radius . The Tychonoff theorem makes the product of these disks over all compact. Consequently the net of vectors has a convergent subnet. Call its coordinatewise limit . Since each finite average is linear, positive on nonnegative real functions, and equal to one at the constant function one, the limit satisfiesand . Thus is a bounded positive linear functional.
Given an identity neighbourhood , continuity of multiplication and inversion supplies a sufficiently small with . The translation estimate consequently tends to zero along the subnet. For every and every ,The Riesz-Markov-Kakutani representation theorem now represents by a regular positive Borel measure with . The preceding equality and uniqueness in that representation imply that the pushforward under every left translation equals . HenceThis is the required normalized Haar measure. It is nonzero because its total mass is one. In fact every nonempty open set has positive measure: its left translates cover , a finite subcover exists, and a zero measure for that open set would force .
For completeness, the constructed probability measure is also right invariant. Apply Fubini's theorem to with both variables distributed according to . Integrating first in gives by left invariance. Integrating first in and substituting gives . Thus is invariant under inversion. Inversion turns a right translation into a left translation, so right invariance follows. This last observation is not needed for the existence of a left Haar measure, but confirms the usual two-sided normalization for compact groups.