Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 310 4 c Solution Created 2026-10-03 Updated 2026-10-06
For the monomial inflation potential on , and . Thus, to leading slow-roll approximation,For , . Therefore the loose order-one requirements and giveThis is the interpretation under which the printed threshold follows. It is not a sufficient criterion for genuine slow roll, which requires much smaller parameters and hence for these fixed powers. Nor is its equality the actual end of acceleration for : there . For the leading estimate has . The potential-based order-one criterion also differs from the Hubble-flow criterion, especially at . We use the endpoint the paper explicitly stipulates, rather than treating this boundary as a controlled slow-roll approximation.
Let by that prescription. The slow-roll e-fold count, using , isFor , the monomial inflation with a prescribed endpoint result isApplying the leading scalar spectral index in Hubble slow-roll parameters and tensor-to-scalar ratio formulas givesThese are predictions at the chosen 60-e-fold initial point, normally identified with the pivot scale's horizon exit. A physical endpoint determined by would instead have the leading estimate ; its change to the e-fold count and predictions must not be silently mixed with the stipulated calculation.
Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 310 4 d Solution Created 2026-10-03 Updated 2026-10-06
Using the leading predictions just obtained givesThe quadratic and cubic monomial inflation potentials satisfy the quoted interval for the scalar spectral index, whereas the quartic model lies below its lower endpoint. All three exceed the quoted bound on the tensor-to-scalar ratio. ThusThis conclusion uses the exam's numerical bounds and the specified 60-e-fold endpoint convention, not a substitution of later observational constraints. Even a modest endpoint adjustment does not reduce the predicted by the roughly factor of two or more needed here.
Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 310 4 e Solution Created 2026-10-03 Updated 2026-10-06
The initial field values are , approximately , and for the three powers. A simple monomial inflation potential over this super-Planckian field range needs theoretical protection. Generic Planck-suppressed corrections to inflaton potentials, such as , need not be small there; they can change the slope and curvature and spoil slow-roll inflation. Radiative corrections and possible couplings to other particles likewise require control. A symmetry, such as an approximate scalar-field shift symmetry, or a specified ultraviolet completion could supply that protection, but it is not part of the bare monomial model.
A large field value is not by itself a proof that the energy density is Planckian: a sufficiently small can keep . The issue is control of the effective field theory and stability of the flat potential over its field range, rather than simply comparing the field value with a mass scale.
There is also a global potential issue for : continued over all real is unbounded below and has no stable minimum at zero. Restricting to does not specify what happens when the field reaches that boundary, so a completion is needed for post-inflationary evolution and reheating. The even powers have a stable minimum but still need interactions that transfer the inflaton energy to a hot bath. These interactions and the resulting reheating history also affect the mapping between a pivot scale and the assumed 60 number of e-folds. Therefore the concise theoretical concerns are control of large-field corrections, a consistent stable completion, and a specified reheating mechanism.
Past exam of the mathematics course of the University of Cambridge 2019 iii Paper 310 1 d Solution Created 2026-10-03 Updated 2026-10-05
The identityshows that accelerating expansion has and , whereas accelerated contraction has , , and .
For the monomial inflation potential , the two potential slow-roll parameters areThus requires , while requires .
At , the specified velocity gives kinetic energyHence , , and the first Hubble slow-roll parameter isThe universe is therefore decelerating, despite the flatness of the potential: the chosen initial kinetic energy violates the slow-roll approximation.
Past exam of the mathematics course of the University of Cambridge 2022 iii Paper 310 4 c Solution 2026-09-28
In an effective field theory, higher-power terms in an inflaton scalar potential can be important when is large, even if is small. An assumed simple monomial inflation potential over such a field range needs a symmetry or ultraviolet completion controlling these operators and radiative corrections. A large field value alone does not establish Planckian energy density or invalidate every possible completion.