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{title2=$N=\log(a/a_i)$}

The number of e-folds during an interval of expansion is the logarithmic growth of the <scale factor>:
$$
N=\log\frac{a_f}{a_i}=\int_{t_i}^{t_f}H\,dt.
$$

Number of e-folds

Past exam of the mathematics course of the University of Cambridge / 2019 / ii / Paper 1 / 15B / c / Solution

Past exam of the mathematics course of the University of Cambridge / 2019 / ii / Paper 1 / 15B / e / Solution

Number of e-folds ( $N = lo g (a / a_{i})$ )

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Number of e-folds (N=log(a/ai​))

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Number of e-folds ( $N = lo g (a / a_{i})$ )

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