Completeness of Lebesgue measure Created 2026-09-24 Updated 2026-10-31
Every subset of a Lebesgue null set is a Lebesgue measurable set and is itself a null set. In fact the same conclusion follows directly from , without assuming measurability in advance. For any , monotonicity of Lebesgue outer measure gives and . Therefore
The reverse inequality follows from countable subadditivity of Lebesgue outer measure, applied to the union . This is Carathéodory's criterion, proving measurability. If is a subset of an outer-null , its outer measure is zero by the same monotonicity. Thus the restriction of outer measure to measurable sets is a complete measure.
A subset is a Lebesgue measurable set when it satisfies Carathéodory's criterion: for every ,
Suppose and let , allowing . The monotonicity of Lebesgue outer measure follows directly from covers: every cover of a larger set covers a smaller set. Thus , while . Consequently
The reverse inequality is countable subadditivity of Lebesgue outer measure applied to . Equality follows, even if . Therefore and every subset are Lebesgue measurable sets of measure zero. This is the completeness of Lebesgue measure, obtained without presupposing measurability of the outer-null set.
If and is a null set, every interval cover of also covers . Thus monotonicity of Lebesgue outer measure gives . Hence every subset of a null set is null, and in particular is Lebesgue measurable.
If and is a null set, every interval cover of also covers . Thus monotonicity of Lebesgue outer measure gives . Hence every subset of a null set is null, and in particular is Lebesgue measurable.