Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 126 1 b Solution Created 2026-09-24 Updated 2026-09-25
In (i), the coordinate map is , , andIt is therefore a free module of rank two and the morphism is flat, including in characteristic two.
In (ii), is finite over the cusp ring and has generic rank one. Were it flat, finite flatness over the local ring at the cusp would make it free of rank one. Its fiber there is insteadwhich has dimension two, so this morphism is not flat.
In (iii), the base coordinate acts as , and the nonzero element satisfies . Thus the coordinate ring has torsion as a -module. Since is a principal ideal domain and a module over it is flat exactly when it is torsion-free, this morphism is not flat. Consequently
Past exam of the mathematics course of the University of Cambridge 2026 iii Paper 113 4 a Solution Created 2026-09-24 Updated 2026-09-25
A morphism of schemes is a closed immersion if it identifies homeomorphically with a closed subset of and the morphism of sheavesis surjective. Equivalently, every point of has an affine neighborhood on which is isomorphic to for some ideal .
A closed subscheme of is a scheme supplied with a closed immersion , considered up to isomorphism over .