Use the proton labels in the original drawing below. Let denote the three methyl hydrogens, the crotonyl beta-CH, the crotonyl alpha-CH, the O-bound vinyl CH, and the terminal vinyl hydrogens trans and cis to , respectively.The integrals sum to eight hydrogens. Multiplet centres give the chemical shifts; a peak label at one edge of a multiplet is not its centre. The terminal vinyl hydrogens are chemically nonequivalent because one is cis and the other trans to the O-bound vinyl hydrogen. Each crotonyl CH couples to the other and to the methyl group; the resolved long-range interaction makes the methyl a doublet of doublets rather than a simple doublet.
Original structure showing all eight hydrogens, their environments and calculated NMR coupling constants
. Details. Use the NMR coupling constant conversion . At , separating the overlapping quartets givesThe doublet separation independently gives . For , the two quartets are and ppm; simply taking adjacent lines in their combined ordering would mix different scalar spin-spin couplings.
The methylene quartet gives an average adjacent spacing ppm, or . Thus its printed rounded positions agree with the methyl-derived value to about ; quote the ethyl NMR coupling constant as approximately –. The large vinylic value supports the trans arrangement. The arrows below join the interacting nuclei; each arrow to represents the same interaction with each equivalent fluorine nucleus.
Calculated scalar spin-spin couplings for the vinylic, ethyl and trifluoromethyl sites
. Details. At a carbon-13 resonance frequency of , the three resolved NMR coupling constants areEach is the spacing of adjacent lines within its own quartet. The lower panel of the original coupling diagram in 1(b)(ii) marks the corresponding carbon–fluorine interactions. The bond superscripts count bonds along the connecting path; they are not additional numerical factors multiplying .

