Octahedral molecular geometry 2026-10-20
In octahedral molecular geometry, six donor directions point toward the vertices of an octahedron. Three mutually cis donors can occupy one face; three coplanar donor directions can occupy a meridian.
Octahedral splitting 2026-10-20
Past exam of the chemistry B course of the University of Cambridge 2022 Paper 2 B6 c Solution 2026-10-20
Four equivalents of base remove the four carboxylic-acid protons from two ligand molecules, giving two dianionic pyridine-2,5-dicarboxylate linkers per Pt/Mn pair. The ring nitrogen and neighbouring 2-carboxylate supply a five-membered N,O chelate. A consistent chain has Pt(II), NO, with square planar molecular geometry, and Mn(II), O, with octahedral molecular geometry.
At each Pt, two ligands bind through their ring N and one O of the adjacent 2-carboxylate; their remote 5-carboxylates point toward successive Mn sites. At each Mn, a remote carboxylate from each of two neighbouring Pt-containing units binds through both O atoms. Two coordinated water molecules complete Mn's six-coordinate sphere. The repeating connectivity, with each bracket denoting a single organic linker, isEach Pt has a second N,O chelate extending in the opposite chain direction; each Mn similarly receives two carboxylate chelates. The original donor-connectivity diagram makes those counts explicit.
Pt(II) is and strongly favours square planar molecular geometry. Its affinity for the pyridyl N donor and the chelate effect select the mixed N,O pocket. Mn(II) is high-spin , is harder, and favours the carboxylate and water O donors; six-coordinate octahedral molecular geometry is natural in water. Charge balance per repeat is . A suitable repeat formulation is . This is a justified proposed coordination chain, not a unique crystal structure established from stoichiometry alone; water content, carboxylate bridging modes and actual porosity require structural characterization.
Past exam of the chemistry B course of the University of Cambridge 2022 Paper 2 B7 a ii Solution 2026-10-20
Six neutral ammonia donors leave Cu(II), , soThe donor skeleton has octahedral molecular geometry with a pronounced tetragonal Jahn–Teller distortion, normally four shorter equatorial and two longer axial Cu–N distances. The occupation is orbitally degenerate in the ideal octahedral limit. An electron count above 18 is not a contradiction: ammonia is primarily a sigma donor and the occupied metal-derived antibonding levels make this a weak-field coordination complex rather than a low-valent carbonyl closed shell.
Past exam of the chemistry B course of the University of Cambridge 2023 Paper 2 B6 a ii Solution 2026-10-20
cisplatin has square planar molecular geometry and a metal centre. Choose and along the four Pt–donor directions. The strongly antibonding orbital is highest and remains empty; the other four d orbitals are doubly occupied. The square-planar splitting is represented by the conventional qualitative orderThe ordering among the lower occupied levels can depend on the ligand set, and the cis arrangement removes exact fourfold symmetry. The robust result is the filled lower four levels and empty highest level.
satraplatin has approximately octahedral molecular geometry around Pt(IV), . Its large octahedral splitting favours a low-spin complex:All three orbitals are paired. Mixed ligands remove exact degeneracies, but do not change this qualitative occupancy.
Past exam of the chemistry B course of the University of Cambridge 2024 Paper 2 B7 c Solution 2026-10-20
Start from an octahedral molecular geometry with ligands on , with above . Remove the donor while keeping the other five positions. Loss of axial repulsion lowers substantially; still points directly at four basal donors and remains highest. Loss of an axial donor also lowers the orbitals with dependence relative to . The remaining fourfold axis keeps and degenerate.
The usual qualitative square-pyramidal molecular geometry diagram, shown in the last panel above, is thereforeThe corresponding labels are . Energies can be re-zeroed to the new orbital barycenter after ligand removal. Symmetry fixes the degeneracy and labels, but does not universally fix the separation of and : a weak or distant axial donor can reverse this middle pair on approach to the square-planar limit. The displayed ordering assumes an appreciable fifth axial interaction.
Past exam of the chemistry B course of the University of Cambridge 2025 Paper 2 B6 b v Solution 2026-10-20
Both complexes contain cobalt(III), hence a metal ion. The approximately octahedral molecular geometry, relatively high metal oxidation state and five ammonia donors make the octahedral splitting large enough that pairing is favorable. Their low-spin configuration isAll six metal electrons are paired, and the ligands in coordination chemistry have closed shells, so neither complex has a permanent spin magnetic moment: both exhibit diamagnetism. The difference between N and O attachment is insufficient to change this low-spin assignment.
The isolobal analogy compares fragments through their frontier molecular orbitals: their number, approximate energies, shapes, symmetries and electron occupancies should correspond. It does not require the fragments to have the same total number of electrons or the same constituent elements. If the orbitals available for forming new bonds correspond, analogous ways of joining the fragments become plausible.
For example, and are isolobal. The methyl radical has one singly occupied approximately outward-pointing orbital; removing one carbonyl ligand from an octahedral molecular geometry leaves an analogous frontier orbital on the 17-electron fragment. Joining two such fragments pairs the two electrons: the organic example is the C–C bond of ethane, and the organometallic example is the Mn–Mn bond of . The analogy predicts a bonding pattern, rather than equality of bond energies or reaction rates.[ref]
Building Bridges Between Inorganic and Organic Chemistry (Nobel Lecture) by Roald Hoffmann. 1982, discussion of the methyl and metal-carbonyl fragment analogy
Square-pyramidal molecular geometry 2026-10-20
Square-pyramidal molecular geometry has four basal donor positions in a square and one axial donor. Removing one axial ligand from an octahedral molecular geometry lowers orbitals with character. A common -level order is , although the middle pair depends on axial strength and distances.

