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Mathematics course of the University of Cambridge

Past exam of the mathematics course of the University of Cambridge

2003

Paper 40

The founder $C$ is unrelated to the descendants of $A,B$, while the <kinship coefficient> between $D$ and its parents' sibling $U$ is
$$
\phi_{DU}=\tfrac12(\phi_{VU}+\phi_{WU})=\frac14.
$$
As $G$ has parents $C,U$, the <kinship coefficient> between $D,G$ is
$$
\phi_{DG}=\tfrac12(\phi_{DC}+\phi_{DU})=\tfrac12(0+\tfrac14)=\frac18.
$$
The parents of $E$ are $D,G$, so
$$
\boxed{F_E=\phi_{DG}=\frac18.}
$$
The same calculation gives $F_F=1/8$.

Solution

Past exam of the mathematics course of the University of Cambridge / 2003 / iii / Paper 40 / 6 / b / ii / Solution

Past exam of the mathematics course of the University of Cambridge / 2003 / iii / Paper 40 / 6 / b / ii / Solution

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Past exam of the mathematics course of the University of Cambridge / 2003 / iii / Paper 40 / 6 / b / ii / Solution

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