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Past exam of the mathematics course of the University of Cambridge
/
2018
/
ia
/
Paper 1
/
1C
/
i
/
Solution
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Past exam of the mathematics course of the University of Cambridge
2018
ia
Paper 1
1C
i
Created
2026-09-24
Updated
2026-10-03
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For
z
=
0
, the
principal value
of
complex exponentiation
is
z
w
=
exp
(
w
Log
z
)
, where the
principal complex logarithm
is
Log
z
=
lo
g
∣
z
∣
+
i
Arg
z
with
−
π
<
Arg
z
≤
π
.
De Moivre's theorem
states that
(
cos
θ
+
i
sin
θ
)
n
=
cos
(
n
θ
)
+
i
sin
(
n
θ
)
for every
integer
n
.
Since
3
+
i
=
2
e
iπ
/6
, the six
roots
are
z
=
2
1/6
exp
(
i
(
36
π
+
3
kπ
)
)
,
k
=
0
,
1
,
…
,
5.
(1)
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i
1C
Paper 1
ia
2018
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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