A Möbius transformation of a Papperitz symbol changes the independent variable by a Möbius transformation. In particular,
maps to , respectively. Because a Möbius map is locally biholomorphic away from its pole, it carries each exponent pair with its singular point and gives
Now define a dependent-variable rescaling of a Papperitz symbol by writing the old dependent variable as
so that . This dependent-variable rescaling of a Papperitz symbol subtracts from both exponents at zero, subtracts from both exponents at one, and adds to both exponents at infinity. Hence has symbol
Define
The Fuchs relation gives and . After renaming as , the symbol is therefore
which is the Gauss hypergeometric equation. Renaming as gives exactly the displayed symbol in the question.

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