A Möbius transformation of a Papperitz symbol changes the independent variable by a Möbius transformation. In particular,maps to , respectively. Because a Möbius map is locally biholomorphic away from its pole, it carries each exponent pair with its singular point and givesNow define a dependent-variable rescaling of a Papperitz symbol by writing the old dependent variable asso that . This dependent-variable rescaling of a Papperitz symbol subtracts from both exponents at zero, subtracts from both exponents at one, and adds to both exponents at infinity. Hence has symbolDefineThe Fuchs relation gives and . After renaming as , the symbol is thereforewhich is the Gauss hypergeometric equation. Renaming as gives exactly the displayed symbol in the question.
Articles by others on the same topic
There are currently no matching articles.