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Past exam of the mathematics course of the University of Cambridge
/
2019
/
ii
/
Paper 1
/
4H
/
b
/
iii
/
Solution
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2019
ii
Paper 1
4H
b
iii
Created
2026-09-24
Updated
2026-10-03
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The
equations
3
m
=
4
l
and
2
n
=
5
k
are equivalent to
m
=
4
r
,
l
=
3
r
,
n
=
5
s
,
k
=
2
s
(1)
for nonnegative
integers
r
,
s
. Hence the language is
{
a
4
r
b
5
s
c
2
s
d
3
r
:
r
,
s
≥
0
}
,
(2)
which is the
nested two-pair count language
generated by
S
→
aaaa
S
ddd
∣
T
,
T
→
bbbbb
T
cc
∣
ϵ
.
(3)
It is therefore
context
-
free
.
Ancestors
(12)
iii
b
4H
Paper 1
ii
2019
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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