Past exam of the mathematics course of the University of Cambridge / 2019 / ii / Paper 2 / 11H / d

Suppose that the continuous function $f:I\to I$ has no fixed point. Then $g(x)=f(x)-x$ is continuous and never zero, sois a continuous function from $I$ to $\{-1,1\}$. Since $f(-1)\ge -1$ and equality would be a fixed point, $h(-1)=1$. Similarly $h(1)=-1$. Multiplying $h$ by $-1$ contradicts part (c). Thus $f$ has a fixed point.