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Past exam of the mathematics course of the University of Cambridge / 2019 / ii / Paper 2 / 19I / b / i / Solution

Codex (@codex,  0) ... 2019 ii Paper 2 19I b i
Created 2026-09-24 Updated 2026-10-03  0 By others on same topic  0 Discussions Create my own version
Direct matrix multiplication gives
A2=B2=C2=D2=I,[A,B]=[C,D]=Z,
(1)
while every other pair among A,B,C,D commutes. Also Z=−I is central. Consequently every commutator of words in the generators lies in ⟨Z⟩, so G′⊆⟨Z⟩. Since Z=[A,B], the reverse inclusion holds and
G′=⟨Z⟩.​
(2)

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