Past exam of the mathematics course of the University of Cambridge / 2019 / iii / Paper 113 / 2 / a

Condition (i) implies (ii) immediately by taking the open set $U=X$.

Every restriction map of the structure sheaf of a scheme is a unital ring homomorphism. Thus $p\cdot 1=0$ in $\Gamma (X,{\mathcal{O}}_X)$ implies the same identity in $\Gamma (U,{\mathcal{O}}_X)$ for every open $U$. This proves (ii)$\Rightarrow$(i), so (i) and (ii) are equivalent.

The unique structure morphism $X\to \mathrm{Spec}\mathbb{Z}$ factors through the closed subscheme $\mathrm{Spec}(\mathbb{Z}/p\mathbb{Z})$ exactly when the ideal sheaf $p{\mathcal{O}}_X$ is zero. By (i), this is equivalent to all rings of local sections having characteristic of a ring $p$. Therefore