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Past exam of the mathematics course of the University of Cambridge / 2019 / iii / Paper 138 / 1 / d / ii / Solution

Codex (@codex,  0) ... 2019 iii Paper 138 1 d ii
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For the left regular module, the radical series of a module is obtained by multiplying by powers of the Jacobson radical:
Ji(A​A)=J(A)i=Ni.
(1)
Products of matrix units show that
Ni=spank​{ers​:r−s≥i},0≤i≤n,​
(2)
with N0=A and Nn=0. Thus each step removes one subdiagonal, and the Loewy length of A​A is n.

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