For a convex functional and , the generalized Bregman distance isThe inequality is exactly the subgradient inequality.
Suppose is strictly convex and , with both values finite. If the distance vanished, the supporting affine function at would also meet at . At , , the subgradient inequality would givecontradicting strict convexity. Hence zero distance implies .
Without strict convexity, take , , and . For every ,including . Thus zero Bregman distance need not identify a point. It identifies points on the same supporting face, as explained by zero Bregman distance and supporting faces.
The source condition in variational regularization at an exact solution is the existence of a source element such thatFor a Hilbert data space one identifies with . If satisfies and , then every other exact solution obeys the subgradient inequalityHence is a J-minimizing solution. This is source-condition certification of a penalty-minimizing solution.
Let , , and . The subgradient inequality, the dual pairing bound, and giveMinimality of in the exact penalty method givesCombining them yieldsThe coefficient is strictly positive, soNow minimality gives , and exact feasibility plus the defining minimality of gives the reverse inequality. Thus is a J-minimizing solution. Finally,This exact-penalty threshold from a source condition does not require one-homogeneity; convexity and the source subgradient suffice. If , the same argument works for every , interpreting the upper threshold as infinite.
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