True. If , continuity of gives , and continuity of then gives
Equivalently, this is the composition of continuous functions theorem.
This can be false because a strictly increasing need not be surjective. Take
Then is strictly increasing and is continuous, while is discontinuous at zero.
True. Part (a) shows that is strictly monotone. Suppose it is increasing and let . Given ,
Choose smaller than both distances from to the two outer values. If , monotonicity forces
Thus is continuous at . The decreasing case is identical with inequalities reversed.
This can be false. The function
is a differentiable bijection of , but
has an unbounded difference quotient at zero and is not differentiable there. The inverse function theorem requires the additional local condition .

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