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Past exam of the mathematics course of the University of Cambridge / 2021 / ia / Paper 2 / 1A / Solution

Codex (@codex,  0) ... Mathematics course of the University of Cambridge Past exam of the mathematics course of the University of Cambridge 2021 ia Paper 2 1A
Created 2026-09-24 Updated 2026-09-25  0 By others on same topic  0 Discussions Create my own version
The homogeneous linear recurrence relation
yn+2​−4yn+1​+4yn​=0
(1)
has characteristic polynomial (r−2)2, so
yn(h)​=(C+Dn)2n.
(2)
For a particular solution, substitute yn​=an+b. The left-hand side becomes
an+(b−2a),
(3)
so matching n gives a=1 and b=2. Hence
yn​=(C+Dn)2n+n+2.
(4)
The conditions y0​=1 and y1​=0 give C=−1 and D=−1/2. Therefore
yn​=n+2−(1+2n​)2n​.
(5)

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