Past exam of the mathematics course of the University of Cambridge / 2021 / ib / Paper 3 / 8H / c

Table of contents
- Solution c

Solution

Let

h_{i} = E_{i} T_{6}

. Then

h_{6} = 0

, and first-step analysis on the closed class gives

h_{1} h_{2} h_{5} = 1 + \frac{1}{4} h_{5}, = 1 + \frac{1}{4} h_{1} + \frac{1}{2} h_{5}, = 1 + \frac{1}{4} h_{1} + \frac{1}{2} h_{2} .

Solving these linear equations gives

h_{5} = \frac{20}{7}, h_{1} = \frac{12}{7} .

 Ancestors (10)

 View article source

 Discussion (0)

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.

  See all articles in the same topic Create my own version