Starting with , choose for as long asThe union of these translates lies in , whose size is at most by part a. The first translate contributes , and every later translate contributes at least , soLet . Maximality says that, for each , more than half of the elements satisfyfor some . Given , the two corresponding subsets of each have more than elements, so they intersect. For an in their intersection there are and such thatSubtracting givesAs every element of is some , this proves
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