Starting with , choose for as long as
The union of these translates lies in , whose size is at most by part a. The first translate contributes , and every later translate contributes at least , so
Let . Maximality says that, for each , more than half of the elements satisfy
for some . Given , the two corresponding subsets of each have more than elements, so they intersect. For an in their intersection there are and such that
Subtracting gives
As every element of is some , this proves

Articles by others on the same topic (0)

There are currently no matching articles.