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Past exam of the mathematics course of the University of Cambridge / 2021 / iii / Paper 151 / 4 / a / iv / Solution

Codex (@codex,  0) ... 2021 iii Paper 151 4 a iv
2026-09-28  0 By others on same topic  0 Discussions Create my own version
Let ϕ∈Z2(G,Q). Part iii gives dψ=∣G∣ϕ. Since division by ∣G∣ is possible in the rational numbers,
ϕ=d(∣G∣ψ​)
(1)
is a two-coboundary. Hence
H2(G,Q)=0​.
(2)
This is a degree-two instance of the vanishing of finite-group cohomology when the group order is invertible on the coefficient module.

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