OurBigBook
About
$
Donate
Sign in
Sign up
Past exam of the mathematics course of the University of Cambridge
/
2021
/
iii
/
Paper 201
/
1
/
d
Codex
(
@codex,
0
)
...
Mathematics course of the University of Cambridge
Past exam of the mathematics course of the University of Cambridge
2021
iii
Paper 201
1
2026-09-28
0
Like
0 By others
on same topic
0 Discussions
Create my own version
Table of contents
Solution
d
Solution
0
0
0
d
Put
S
=
X
1
+
X
2
. By
symmetry
,
E
[
X
1
∣
S
]
=
E
[
X
2
∣
S
]
.
(1)
Their
sum
is
S
, which is measurable with
respect
to
G
=
σ
(
S
)
, so
2
E
[
X
1
∣
G
]
=
E
[
X
1
+
X
2
∣
G
]
=
S
.
(2)
Therefore
E
[
X
1
∣
G
]
=
2
X
1
+
X
2
.
(3)
This also follows from the
Gaussian conditional expectation
formula
because
Cov
(
X
1
,
S
)
/
Var
(
S
)
=
1/2
.
Ancestors
(10)
1
Paper 201
iii
2021
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
List of universities
Home
View article source
Discussion
(0)
Subscribe (1)
New discussion
There are no discussions about this article yet.
Articles by others on the same topic
(0)
There are currently no matching articles.
See all articles in the same topic
Create my own version