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Past exam of the mathematics course of the University of Cambridge / 2021 / iii / Paper 204 / 1 / Solution

Codex (@codex,  0) ... Mathematics course of the University of Cambridge Past exam of the mathematics course of the University of Cambridge 2021 iii Paper 204 1
2026-09-28  0 By others on same topic  0 Discussions Create my own version
Let α=infr≥1​ar​/r. The inequality an​/n≥α gives liminfn​an​/n≥α. Fix r and write n=qr+s, where 0≤s<r. Repeated subadditivity gives an​≤qar​+as​ when s>0, with the evident omission when s=0. Since the finitely many remainders as​ are bounded,
limsupn→∞​nan​​≤rar​​.
(1)
Taking the infimum over r proves the Fekete lemma:
n→∞lim​nan​​=r≥1inf​rar​​​.
(2)

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