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Past exam of the mathematics course of the University of Cambridge
/
2022
/
ia
/
Paper 2
/
11F
/
d
/
Solution
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Past exam of the mathematics course of the University of Cambridge
2022
ia
Paper 2
11F
d
Created
2026-09-24
Updated
2026-09-25
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Let
E
j
be the expected additional
number
of tosses when the current terminal run contains
j
consecutive heads. Then
E
k
=
0
, and for
0
≤
j
<
k
,
E
j
=
1
+
p
E
j
+
1
+
(
1
−
p
)
E
0
.
(1)
For
0
<
p
<
1
, iterating this recurrence from
j
=
k
−
1
down to
0
gives
E
0
=
(
1
+
(
1
−
p
)
E
0
)
1
−
p
1
−
p
k
.
(2)
Solving,
E
0
=
(
1
−
p
)
p
k
1
−
p
k
.
(3)
When
p
=
1
, the waiting
time
is deterministically
k
, which is also the continuous limit of this
formula
as
p
→
1
.
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(11)
d
11F
Paper 2
ia
2022
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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