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Past exam of the mathematics course of the University of Cambridge
/
2022
/
ib
/
Paper 1
/
14B
/
c
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Mathematics course of the University of Cambridge
Past exam of the mathematics course of the University of Cambridge
2022
ib
Paper 1
14B
Created
2026-09-23
Updated
2026-09-24
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Solution
c
Solution
0
0
0
c
Put
u
=
a
+
iω
t
. Then
F
˙
=
iω
A
sech
2
u
,
G
˙
=
−
iω
ℏ
mω
sech
u
tanh
u
.
(1)
The
G
equation
from part (
b
) is satisfied when
m
2
ℏ
2
A
=
ℏ
ω
,
(2)
so
A
=
2ℏ
mω
.
(3)
With this value, the
F
equation
follows from
tanh
2
u
=
1
−
sech
2
u
: both its constant and
sech
2
u
coefficients
agree. Thus the stated
F
,
G
satisfy both
shape
equations
; the remaining
scalar
equation
determines the normalization factor
N
(
t
)
.
Ancestors
(10)
14B
Paper 1
ib
2022
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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