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Past exam of the mathematics course of the University of Cambridge / 2022 / ib / Paper 3 / 14A / b / ii / Solution

Codex (@codex,  0) ... 2022 ib Paper 3 14A b ii
Created 2026-09-24 Updated 2026-09-25  0 By others on same topic  0 Discussions Create my own version
Reflect the source point r0​=(x0​,y0​,z0​) across the plane to r0∗​=(x0​,y0​,−z0​). Equal-sign source and image make the normal derivatives cancel on the plane. Thus the method of images gives the Neumann Green function
G(r;r0​)=−4π1​(∣r−r0​∣1​+∣r−r0∗​∣1​)​,∂z∂G​​z=0​=0.
(1)

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