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Past exam of the mathematics course of the University of Cambridge
/
2022
/
ii
/
Paper 1
/
31J
/
c
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Mathematics course of the University of Cambridge
Past exam of the mathematics course of the University of Cambridge
2022
ii
Paper 1
31J
Created
2026-09-23
Updated
2026-09-24
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Table of contents
i
c
Solution
i
ii
c
Solution
ii
i
0
0
0
c
Solution
0
0
0
i
Fix sample points
(
x
i
,
z
i
)
,
1
≤
i
≤
n
.
A
labeling by
h
(
x
,
z
)
=
f
(
x
)
g
(
z
)
is the coordinatewise product of one labeling that
F
realizes on
x
1
,
…
,
x
n
and one that
G
realizes on
z
1
,
…
,
z
n
. There are at most the product of the two
numbers
of
choices
, so
s
(
H
,
n
)
≤
s
(
F
,
n
)
s
(
G
,
n
)
.
(1)
ii
0
0
0
c
Solution
0
0
0
ii
For fixed
x
1
,
…
,
x
n
, the
vector
(
h
(
x
1
)
,
…
,
h
(
x
n
))
(1)
is again the coordinatewise product of
a
labeling realized by
F
and one realized by
G
, now on the same sample. Hence there are at most
s
(
F
,
n
)
s
(
G
,
n
)
(2)
possible products. Maximizing over samples proves the claimed inequality.
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(10)
31J
Paper 1
ii
2022
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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