Past exam of the mathematics course of the University of Cambridge / 2022 / ii / Paper 1 / 38D / a

Table of contents
- Solution a

Solution

For

k = - 1

, the Friedmann-Lemaitre-Robertson-Walker metric is

d s^{2} = - d t^{2} + a^{2} (t) [d χ^{2} + sinh^{2} χ (d θ^{2} + sin^{2} θ d ϕ^{2})] .

The empty first Friedmann equation, with

Λ = 0

, gives

\frac{a ˙ ^{2} - 1}{a ^{2}} = 0.

Choosing the expanding branch and shifting the origin of proper time yields

a (t) = t, t > 0 .

 Ancestors (10)

 View article source

 Discussion (0)

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.

  See all articles in the same topic Create my own version