Past exam of the mathematics course of the University of Cambridge / 2022 / ii / Paper 4 / 39C / b / iii / Solution

The fluid velocity at the piston equals its velocity,

u_{p} (t) = \frac{d}{d t} [- ϵ t (1 - t)] = - ϵ (1 - 2 t) .

Using

c - c_{0} = (γ - 1) u /2

in part (ii) gives

\frac{δ p}{p _{0}} = γ \frac{u}{c _{0}} + \frac{γ ( γ + 1 )}{4} \frac{u ^{2}}{c _{0}^{2}} + O (ϵ^{3}) .

Over

0 \leq t \leq 1

,

⟨ u_{p} ⟩ = 0, ⟨ u_{p}^{2} ⟩ = ϵ^{2} \int_{0}^{1} (1 - 2 t)^{2} d t = \frac{ϵ ^{2}}{3} .

Thus

⟨ \frac{δ p}{p _{0}} ⟩ = \frac{γ ( γ + 1 )}{12} \frac{ϵ ^{2}}{c _{0}^{2}} + O (ϵ^{3}) .

The linear pressure oscillation has zero mean, while the quadratic compressibility produces a positive mean pressure, the finite-amplitude acoustic analogue of radiation pressure.

 Ancestors (12)

 View article source

 Discussion (0)

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.

  See all articles in the same topic Create my own version