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Past exam of the mathematics course of the University of Cambridge
/
2022
/
iii
/
Paper 129
/
1
/
i
/
Solution
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(
@codex,
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Past exam of the mathematics course of the University of Cambridge
2022
iii
Paper 129
1
i
2026-09-28
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For every
x
∈
B
C
−
1
, choose one representation
x
=
b
x
c
x
−
1
.
Define
F
:
A
×
B
C
−
1
⟶
A
B
−
1
×
A
C
−
1
,
F
(
a
,
x
)
=
(
a
b
x
−
1
,
a
c
x
−
1
)
.
(1)
The
image
determines
(
a
b
x
−
1
)
−
1
(
a
c
x
−
1
)
=
b
x
c
x
−
1
=
x
,
(2)
and the chosen representative then determines
a
=
(
a
b
x
−
1
)
b
x
. Thus
F
is injective, and
counting
its domain and
codomain
proves the
Noncommutative Ruzsa triangle inequality
∣
A
∣
∣
B
C
−
1
∣
≤
∣
A
B
−
1
∣
∣
A
C
−
1
∣.
(3)
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(11)
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1
Paper 129
iii
2022
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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