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Past exam of the mathematics course of the University of Cambridge / 2022 / iii / Paper 201 / 2 / b / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2022 iii Paper 201 2 b
2026-09-28  0 By others on same topic  0 Discussions Create my own version
After replacing Xj​ by Xj​−μ, the maximal inequality for independent averages gives
​supm≥1​m∣Sm​∣​​Lp​≤Cp​∥X1​∥Lp​,p>1.
(1)
This follows from the Doob Lp maximal inequality by dyadically grouping the partial sums. The strong law makes
supm≥n​m∣Sm​∣​⟶0
(2)
almost surely. The displayed maximal function is in Lp, so dominated convergence applied to its pth power proves convergence in Lp.

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