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Past exam of the mathematics course of the University of Cambridge / 2022 / iii / Paper 215 / 1 / d / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2022 iii Paper 215 1 d
2026-09-28  0 By others on same topic  0 Discussions Create my own version
Take τ0​=0 and apply part c recursively. A lazy walk makes a genuine jump with probability 1/2, so the expected time required for 2j jumps is 4j. Using the stated independence,
E0​τk​=4E0​τk−1​+1.
(1)
The initial value zero solves this recurrence as
E0​τk​=34k−1​.
(2)

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